A table with smooth horizontal surface is rotating at a speed ω ω about its axis. A groove is made on the surface along a radius and a particle is gently placed inside the groove at a distance a from the centre. Find the speed of the particle with respect to the table as its distance from the centre becomes l .
A
v = ω ω l
B
v = ω ω ( l - a)
C
v = 
D
v = ω ω 
Text Solution
Verified by ExpertsThe correct answer is:
D
V dv = ω ω 2 x dx
v = ω ω 
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